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9x^2+22.5x=0
a = 9; b = 22.5; c = 0;
Δ = b2-4ac
Δ = 22.52-4·9·0
Δ = 506.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22.5)-\sqrt{506.25}}{2*9}=\frac{-22.5-\sqrt{506.25}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22.5)+\sqrt{506.25}}{2*9}=\frac{-22.5+\sqrt{506.25}}{18} $
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